F(x)=3x^2+6-5

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Solution for F(x)=3x^2+6-5 equation: 



(F)=3F^2+6-5

We move all terms to the left:

(F)-(3F^2+6-5)=0

We get rid of parentheses

-3F^2+F-6+5=0

We add all the numbers together, and all the variables

-3F^2+F-1=0

a = -3; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-3)·(-1)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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